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12 BLJBCTRIC DISCHARGE* WAVM* 4JVI>
to produce the magnetic*, field fl> of the current i» a voltage *•'
must be consumed in the circuit, which with the* current i given the power p, which supplier the ntowl energy i/» of the magnetic* field *. This voltage / IB called the inttHCttmw fW/(ff|f, or wllngv consumed try $d/~indmti(m»
Since no power in required to maintain the fleM, but. {tower in
required to produce it, the inductance voltage must IN* pmpor- tional to the rate of increaHe of the magnetic field: |
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or by (1),
«'«//jj. (4)
tii
If i and therefore * (Uwreaw, .. and t hwfw r nn» t |
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that is, p becomes nogativt*, and i>ower h rctiiritetl iiitu the circuit.
The energy supplied by the power |i h
w « I |i rf/,
or by (2) and (4),
w ^ IIJ rff;
t'
hence
//P ,-.
W)--2* (ft)
is the energy of the magnetic* fiehl
4* » /4*
of the circuit.
9, Exactly analogous rwlatlonn in thu <U«»lHttrw fieltL
Th© dielectric field, or dfaketric Jlwt, ^t w iiriipurtiiiitiil fn the
voltage e, with a proportionality factor, (7, which in onHinl flu* capacity o/ tte circuit;
N? «• Cu. (0)
The dielectric field roprtwenti ntoretl tm«myt ID, To prtMhiai Itf
power, p, must^th»afor% be nupplioci by th<$ drcuit,
Since power is current ilmm voltftKo;
p - f e, (7)
to, produce the dielectric field ¥ of thti voltogit et a {nirnmt T
most be consumed in the circuit, which with tiio vultnici^ r |
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